10w^2-30w+20=0

Solution for 10w^2-30w+20=0 equation:

10w^2-30w+20=0

a = 10; b = -30; c = +20;
Δ = b2-4ac
Δ = -302-4·10·20
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-10}{2*10}=\frac{20}{20}
=1
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+10}{2*10}=\frac{40}{20}
=2
$